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TX IQ Mixer

We want to upconvert our baseband signal, \(\omega_{bb}\) , to an RF frequency, \(\omega_{lo}+\omega_{bb}\). The easiest and probably the only way alive of doing so is to multiply \(\omega_{bb}\) signal with \(\omega_{lo}\) signal. This works and generates two sidebands, \(\omega_{lo}+\omega_{bb}\) & \(\omega_{lo}-\omega_{bb}\). But in almost all of the applications today, you just want to transmit a single sideband, either \(\omega_{lo}+\omega_{bb}\) called as upper sideband or \(\omega_{lo}-\omega_{bb}\) called as lower sideband. How do we do that? IQ mixers. They let you cancel out an undesired sideband and many baseband emissions. Image below shows a typical TX with IQ Mixer.
TX Quadrature Mixer

TX IQ Mixer – Math & Insights

Consider an IQ transmitter. I channel DAC generates cosine signal, and Q channel DAC generates 0.25\(T_{bb}\) shifted signal of I channel (or in other words 90 degree shifted for fundamental):

$$ DAC: I(t) = Vcos(\omega_{bb}\,t)$$ $$ DAC: Q(t) = Vcos(\omega_{bb}\,t - \frac{\pi}{2})$$
This signal passes through some baseband circuit, say a baseband amplifier which adds 3rd and 5th order non-linearity. Signal at baseband amplifier output can be written as:
$$ BBF: I(t) = \textcolor{#40ce80}{A_1\,cos(\omega_{bb}\,t)}+\textcolor{#feda39}{A_3\,cos(3\omega_{bb}\,t)}+\textcolor{#e74c3c}{A_5\,cos(5\omega_{bb}\,t)}$$ $$ BBF: Q(t) = A_1\,cos(\omega_{bb}\,t -\frac{\pi}{2})+A_3\,cos(3\omega_{bb}\,t-\frac{3\pi}{2})+A_5\,cos(5\omega_{bb}\,t-\frac{5\pi}{2})\:(delay \; means \; proportional \; phase \; shifts)$$ $$ BBF: Q(t) = \textcolor{#40ce80}{A_1\,sin(\omega_{bb}\,t)}-\textcolor{#feda39}{A_3\,sin(3\omega_{bb}\,t)}+\textcolor{#e74c3c}{A_5\,sin(5\omega_{bb}\,t)}$$

where \(A_{1}\) is a linear gain coefficient, \(A_{3}\) is 3rd order distortion coefficient and \(A_{5}\) is 5th order distortion coefficient. Read more on this in single tone distortion.

Consider an LO signal now. I channel LO is a square wave toggling between +/- 1, Q channel LO is \(\frac{T_{LO}}{4}\) delayed copy of I channel LO, delayed not phase shifted (difference is important).  Developing only up to 5th harmonic of square wave, LO signals can be written as:
$$LO: I(t) = \textcolor{#FFFFFF}{\frac{4}{\pi}\left[cos(\omega_{LO}\,t)-\frac{1}{3}cos(3\omega_{LO}\,t)+\frac{1}{5}cos(5\omega_{LO}\,t)\right]}$$ $$LO: Q(t) = \frac{4}{\pi}\left[cos(\omega_{LO}\,t-\frac{\pi}{2})-\frac{1}{3}cos(3\omega_{LO}\,t-\frac{3\pi}{2})+\frac{1}{5}cos(5\omega_{LO}\,t-\frac{5\pi}{2})\right]\:(delay \; means \; proportional \; phase \; shifts)$$ $$LO: Q(t) = \textcolor{#FFFFFF}{\frac{4}{\pi}\left[sin(\omega_{LO}\,t)+\frac{1}{3}sin(3\omega_{LO}\,t)+\frac{1}{5}sin(5\omega_{LO}\,t)\right]}$$

I channel baseband signal is multiplied by I channel LO, and Q with Q. We can write mixer output as:

$$ MIXER:\; I_{BBF}\,(t).I_{LO}\,(t)+Q_{BBF}\,(t).Q_{LO}\,(t)$$

I Channel Mixer Output

\[ \left[ \textcolor{#40ce80}{A_1\,\textcolor{#40ce80}{cos(\omega_{bb}\,t)}}+\textcolor{#feda39}{A_3\,\textcolor{#feda39}{cos(3\omega_{bb}\,t)}}+\textcolor{#e74c3c}{A_5\,\textcolor{#e74c3c}{cos(5\omega_{bb}\,t)}} \right]. \left[ \textcolor{#FFFFFF}{\frac{4}{\pi}\textcolor{#FFFFFF}{cos(\omega_{lo}\,t)}-\frac{1}{3}\textcolor{#FFFFFF}{cos(3\omega_{lo}\,t)}+\frac{1}{5}\textcolor{#FFFFFF}{cos(5\omega_{lo}\,t)}}\right]\\ \] \begin{alignat*}{8} \\ =\frac{4}{\pi} \biggr[ & \textcolor{#40ce80}{A_1cos(\omega_{bb}\,t)}.\textcolor{#FFFFFF}{cos(\omega_{lo}\,t)}\;&-&\;\frac{\textcolor{#40ce80}{A_1}}{\textcolor{#FFFFFF}{3}}\textcolor{#40ce80}{cos(\omega_{bb}\,t)}.\textcolor{#FFFFFF}{cos(3\omega_{lo}\,t)}\;&+&\;\frac{\textcolor{#40ce80}{A_1}}{\textcolor{#FFFFFF}{5}}\textcolor{#40ce80}{cos(\omega_{bb}\,t)}.\textcolor{#FFFFFF}{cos(5\omega_{lo}\,t)}\\ +& \textcolor{#feda39}{A_3cos(3\omega_{bb}\,t)}.\textcolor{#FFFFFF}{cos(\omega_{lo}\,t)}\;&-&\;\frac{\textcolor{#feda39}{A_3}}{\textcolor{#FFFFFF}{3}}\textcolor{#feda39}{cos(3\omega_{bb}\,t)}.\textcolor{#FFFFFF}{cos(3\omega_{lo}\,t)}\;&+&\;\frac{\textcolor{#feda39}{A_3}}{\textcolor{#FFFFFF}{5}}\textcolor{#feda39}{cos(3\omega_{bb}\,t)}.\textcolor{#FFFFFF}{cos(5\omega_{lo}\,t)}\\ +& \textcolor{#e74c3c}{A_5cos(5\omega_{bb}\,t)}.\textcolor{#FFFFFF}{cos(\omega_{lo}\,t)}\;&-&\;\frac{\textcolor{#e74c3c}{A_5}}{\textcolor{#FFFFFF}{3}}\textcolor{#e74c3c}{cos(5\omega_{bb}\,t)}.\textcolor{#FFFFFF}{cos(3\omega_{lo}\,t)}\;&+&\;\frac{\textcolor{#e74c3c}{A_5}}{\textcolor{#FFFFFF}{5}}\textcolor{#e74c3c}{cos(5\omega_{bb}\,t)}.\textcolor{#FFFFFF}{cos(5\omega_{lo}\,t)} \biggr] \\ \\ =\frac{2}{\pi} \biggr[ & \textcolor{#40ce80}{A_1\{cos(\omega_{lo}-\omega_{bb})t+cos(\omega_{lo}+\omega_{bb})t\}}\;&-&\;\textcolor{#40ce80}{\frac{A_1}{3}\{cos(3\omega_{lo}-\omega_{bb})t+cos(3\omega_{lo}+\omega_{bb})t\}}\;&+&\;\textcolor{#40ce80}{\frac{A_1}{5}\{cos(5\omega_{lo}-\omega_{bb})t+cos(5\omega_{lo}+\omega_{bb})t\}}\\ +& \textcolor{#feda39}{A_3\{cos(\omega_{lo}-3\omega_{bb})t+cos(\omega_{lo}+3\omega_{bb})t\}}\;&-&\;\textcolor{#feda39}{\frac{A_3}{3}\{cos(3\omega_{lo}-3\omega_{bb})t+cos(3\omega_{lo}+3\omega_{bb})t\}}\;&+&\;\textcolor{#feda39}{\frac{A_3}{5}\{cos(5\omega_{lo}-3\omega_{bb})t+cos(5\omega_{lo}+3\omega_{bb})t\}}\\ +& \textcolor{#e74c3c}{A_5\{cos(\omega_{lo}-5\omega_{bb})t+cos(\omega_{lo}+5\omega_{bb})t\}}\;&-&\;\textcolor{#e74c3c}{\frac{A_5}{3}\{cos(3\omega_{lo}-5\omega_{bb})t+cos(3\omega_{lo}+5\omega_{bb})t\}}\;&+&\;\textcolor{#e74c3c}{\frac{A_5}{5}\{cos(5\omega_{lo}-5\omega_{bb})t+cos(5\omega_{lo}+5\omega_{bb})t\}}\biggr]\\ \end{alignat*}
SSB mixer output

A single mixer generates double sideband signal, that is why your output signal (as shown in green color in image above) looks so messed up. It is sum of two sinusoid (along with many other distortion products). Go ahead and add two sinusoids, you will see it will start looking like green signal above. And don’t mind the ringing on the signal, that is because we only considered up to 5 harmonics of LO (add more in your analysis, and it will start going away). Here is how your output spectrum of a single channel mixer will look like:

TX IQ Mixer, TX HRM Mixer, I channel

Q Channel Mixer Output

\[ \left[ \textcolor{#40ce80}{A_1\,\textcolor{#40ce80}{sin(\omega_{bb}\,t)}}-\textcolor{#feda39}{A_3\,\textcolor{#feda39}{sin(3\omega_{bb}\,t)}}+\textcolor{#e74c3c}{A_5\,\textcolor{#e74c3c}{sin(5\omega_{bb}\,t)}} \right]. \left[ \textcolor{#FFFFFF}{\frac{4}{\pi}\textcolor{#FFFFFF}{sin(\omega_{lo}\,t)}+\frac{1}{3}\textcolor{#FFFFFF}{sin(3\omega_{lo}\,t)}+\frac{1}{5}\textcolor{#FFFFFF}{sin(5\omega_{lo}\,t)}}\right]\\ \] \begin{alignat*}{8} \\ =\frac{4}{\pi} \biggr[ & \textcolor{#40ce80}{A_1sin(\omega_{bb}\,t)}.\textcolor{#FFFFFF}{sin(\omega_{lo}\,t)}\;&+&\;\frac{\textcolor{#40ce80}{A_1}}{\textcolor{#FFFFFF}{3}}\textcolor{#40ce80}{sin(\omega_{bb}\,t)}.\textcolor{#FFFFFF}{sin(3\omega_{lo}\,t)}\;&+&\;\frac{\textcolor{#40ce80}{A_1}}{\textcolor{#FFFFFF}{5}}\textcolor{#40ce80}{sin(\omega_{bb}\,t)}.\textcolor{#FFFFFF}{sin(5\omega_{lo}\,t)}\\ -& \textcolor{#feda39}{A_3sin(3\omega_{bb}\,t)}.\textcolor{#FFFFFF}{sin(\omega_{lo}\,t)}\;&-&\;\frac{\textcolor{#feda39}{A_3}}{\textcolor{#FFFFFF}{3}}\textcolor{#feda39}{sin(3\omega_{bb}\,t)}.\textcolor{#FFFFFF}{sin(3\omega_{lo}\,t)}\;&-&\;\frac{\textcolor{#feda39}{A_3}}{\textcolor{#FFFFFF}{5}}\textcolor{#feda39}{sin(3\omega_{bb}\,t)}.\textcolor{#FFFFFF}{sin(5\omega_{lo}\,t)}\\ +& \textcolor{#e74c3c}{A_5sin(5\omega_{bb}\,t)}.\textcolor{#FFFFFF}{sin(\omega_{lo}\,t)}\;&+&\;\frac{\textcolor{#e74c3c}{A_5}}{\textcolor{#FFFFFF}{3}}\textcolor{#e74c3c}{sin(5\omega_{bb}\,t)}.\textcolor{#FFFFFF}{sin(3\omega_{lo}\,t)}\;&+&\;\frac{\textcolor{#e74c3c}{A_5}}{\textcolor{#FFFFFF}{5}}\textcolor{#e74c3c}{sin(5\omega_{bb}\,t)}.\textcolor{#FFFFFF}{sin(5\omega_{lo}\,t)} \biggr] \\ \\ =\frac{2}{\pi} \biggr[ & \textcolor{#40ce80}{A_1\{cos(\omega_{lo}-\omega_{bb})t-cos(\omega_{lo}+\omega_{bb})t\}}\;&+&\;\textcolor{#40ce80}{\frac{A_1}{3}\{cos(3\omega_{lo}-\omega_{bb})t-cos(3\omega_{lo}+\omega_{bb})t\}}\;&+&\;\textcolor{#40ce80}{\frac{A_1}{5}\{cos(5\omega_{lo}-\omega_{bb})t-cos(5\omega_{lo}+\omega_{bb})t\}}\\ -& \textcolor{#feda39}{A_3\{cos(\omega_{lo}-3\omega_{bb})t-cos(\omega_{lo}+3\omega_{bb})t\}}\;&-&\;\textcolor{#feda39}{\frac{A_3}{3}\{cos(3\omega_{lo}-3\omega_{bb})t-cos(3\omega_{lo}+3\omega_{bb})t\}}\;&-&\;\textcolor{#feda39}{\frac{A_3}{5}\{cos(5\omega_{lo}-3\omega_{bb})t-cos(5\omega_{lo}+3\omega_{bb})t\}}\\ +& \textcolor{#e74c3c}{A_5\{cos(\omega_{lo}-5\omega_{bb})t-cos(\omega_{lo}+5\omega_{bb})t\}}\;&+&\;\textcolor{#e74c3c}{\frac{A_5}{3}\{cos(3\omega_{lo}-5\omega_{bb})t-cos(3\omega_{lo}+5\omega_{bb})t\}}\;&+&\;\textcolor{#e74c3c}{\frac{A_5}{5}\{cos(5\omega_{lo}-5\omega_{bb})t-cos(5\omega_{lo}+5\omega_{bb})t\}}\biggr]\\ \end{alignat*}
TX IQ Mixer, TX HRM Mixer, Q channel

I & Q Mixer Output Combined

Now this is where it gets interesting. When I and Q channel outputs are added, a lot of products cancel out. These tones are left out:

\begin{alignat*}{8} \frac{4}{\pi} \biggr[ & \textcolor{#40ce80}{A_1cos(\omega_{lo}-\omega_{bb})t}\;&-&\;\textcolor{#40ce80}{\frac{A_1}{3}cos(3\omega_{lo}+\omega_{bb})t}\;&+&\;\textcolor{#40ce80}{\frac{A_1}{5}cos(5\omega_{lo}-5\omega_{bb})t}\\ +& \textcolor{#feda39}{A_3cos(\omega_{lo}+3\omega_{bb})t}\;&-&\;\textcolor{#feda39}{\frac{A_3}{3}cos(3\omega_{lo}-3\omega_{bb})t}\;&+&\;\textcolor{#feda39}{\frac{A_3}{5}(5\omega_{lo}+3\omega_{bb})t}\\ +& \textcolor{#e74c3c}{A_5cos(\omega_{lo}-5\omega_{bb})t}\;&-&\;\textcolor{#e74c3c}{\frac{A_5}{3}cos(3\omega_{lo}+5\omega_{bb})t}\;&+&\;\textcolor{#e74c3c}{\frac{A_5}{5}cos(5\omega_{lo}-5\omega_{bb})t}\biggr]\\ \end{alignat*}
DSB mixer output signals

Sad. Even when you canceled a sideband, your signal (as shown in green color in image above) still does not look like a sinusoid. Now you can blame distortion products and the fact that each odd harmonic of LO has a copy of your signal+distortions around it. But hey, we cleaned up spectrum a lot, improved gain of our desired sideband, and rejected undesired sideband. And don’t worry, we have more tricks up our sleeves to clean it up further. Intrigued? You are ready to read HRM Mixer.

TX IQ Mixer Spectrum
Author: RFInsights 
Date Published: 15 Jan 2023
Last Edit: 02 Feb 2023